Box Fill & Cartons Needed
How many identical items fit one carton (best of six orientations, block-and-strip rule), the fill percentage, a weight cap, and cartons for an order.
Items per carton with the winning orientation and every alternative, fill %, gross weight, and how many cartons an order needs with the count in the last one — a stated heuristic, not a packing solver.
Example: 10 × 6 × 4 cm items in a 40 × 30 × 20 cm carton: 100 fit by size (20 per layer × 5), but a 20 kg limit less 1 kg tare allows 38; 1,000 pieces need 27 cartons, the last holding 12.
A stated rule,
not a packing solver.
How the count is made, what the orientations mean, and where the weight cap comes in.
The rule
For each way the item can lie, a layer holds a block of ⌊L ÷ l⌋ × ⌊W ÷ w⌋ pieces, plus whatever fits in the leftover strip with the item turned 90°; layers = ⌊H ÷ h⌋. All six orientations are tried (two when the item must stay upright) and the best wins. It is the same rule as the Pallet Fit utility, applied inside a carton.
What it misses
Interlocked, pinwheel or mixed-orientation layers can sometimes beat the block-and-strip count, and real packing needs clearance for the item to go in. Use inner carton dimensions, and subtract padding yourself; the fill percentage tells you how much of the volume the count actually uses.
Weight and cartons
When the carton has a gross limit, the count is capped at ⌊(limit − tare) ÷ item weight⌋ and the page says which constraint won. Cartons for an order = ⌈quantity ÷ per carton⌉, with the count in the last, part-filled carton. Nothing leaves the browser; the same four anonymous usage counts as the rest of the site apply.
SOURCES
- Block-and-strip layer heuristic (same rule as the Pallet Fit utility) over the six item orientations; fill = n × item volume ÷ inner carton volume — no optimal-packing claim
Last reviewed 20 September 2026. How results are checked: How we verify.